In order to calculate the ionization energy of doubly ionized lithium, we need to first understand what ionization energy is. Ionization energy is the minimum amount of energy required to remove the most loosely bound electron from an atom or molecule. For lithium, the most loosely bound electron is the one in the 3s orbital.
To remove this electron, we need to supply enough energy to overcome the electron’s attraction to the nucleus. The strength of this attraction is determined by the nuclear charge, Z. The larger the value of Z, the stronger the attraction and the higher the ionization energy.
Since lithium has a nuclear charge of 3+, the ionization energy of doubly ionized lithium will be higher than that of singly ionized lithium, which has a nuclear charge of 2+.
To calculate the ionization energy of doubly ionized lithium, we use the following equation:
I = Z^2 * R
where I is the ionization energy, Z is the nuclear charge, and R is the Rydberg constant.
Plugging in the values for Z and R, we get:
I = 3^2 * R
I = 9R
Therefore, the ionization energy of doubly ionized lithium is 9 times the Rydberg constant.
Other related questions:
Q: How do you find the ionization energy of li2+?
A: The ionization energy of li2+ is the amount of energy required to remove one electron from a lithium atom in its ground state.
Q: How much energy is required to ionise a doubly ionised lithium?
A: The amount of energy required to ionise a doubly ionised lithium atom is about twice that required to ionise a singly ionised lithium atom.
Q: What is meant by doubly ionized lithium?
A: Doubly ionized lithium is a lithium atom that has lost two electrons, leaving it with a net charge of +2.
Q: What is the formula for ionization energy?
A: Ionization energy is the amount of energy required to remove an electron from an atom or molecule.