It takes 2,257 joules of energy to evaporate 1 gram of water at a standard temperature and pressure (STP). This means that it takes about 2,257 watts of power to evaporate 1 gram of water per second at STP.
Other related questions:
Q: How much energy does it take for water to evaporate?
A: It takes about 600 calories of energy (2,500 joules) to evaporate a pound of water at room temperature.
Q: How many joules does it takes to vaporize 1 gram of water?
A: It takes approximately 2,260 joules to vaporize 1 gram of water.
Q: How many kwh does it take to evaporate 1 kg of water?
A: It takes approximately 2,257 kwh to evaporate 1 kg of water.
Q: How much energy does it take to evaporate a gallon of water?
A: It takes about 9.8 million BTUs of energy to evaporate a gallon of water.