# When 3.0 kg of water is warmed from 10 °c to 80 °c, how much heat energy is needed?

It takes 4184 joules of energy to raise 3 kilograms of water from 10 degrees Celsius to 80 degrees Celsius.

## Other related questions:

### Q: How much heat will be needed to raise the temperature of 1.5 kg of water from 15 C to 45 C?

A: The amount of heat needed to raise the temperature of 1.5 kg of water from 15 C to 45 C can be calculated using the equation:

Q = mcΔT

where Q is the amount of heat (in joules), m is the mass of the water (in kilograms), c is the specific heat of water (4.186 joules per gram per degree Celsius), and ΔT is the change in temperature (in degrees Celsius).

Plugging in the values from the question, we get:

Q = (1.5 kg)(4.186 joules per gram per degree Celsius)(30 degrees Celsius)

Q = 125 joules

### Q: How much heat does it take to change the temperature of water?

A: There is no definitive answer to this question since it depends on a number of factors, such as the initial temperature of the water, the desired final temperature, the specific heat capacity of water, and the heat transfer coefficient.

### Q: What is the heat capacity of 100g of water?

A: The heat capacity of water is 4.184 J/g°C. Therefore, the heat capacity of 100g of water is 418.4 J/°C.

### Q: What is specific heat capacity of water?

A: The specific heat capacity of water is 4.184 J/(g·K).