Mg(g) → Mg2+(g) + 2e−
The second ionization energy of magnesium can be represented by the equation Mg(g) → Mg2+(g) + 2e−. This equation shows that the second ionization energy of magnesium is the energy required to remove two electrons from a magnesium atom in the gaseous state. The second ionization energy of magnesium is greater than the first ionization energy of magnesium because it takes more energy to remove two electrons from an atom than it does to remove just one electron.
Other related questions:
Q: What is the second ionization energy of magnesium?
A: The second ionization energy of magnesium is 1,037 kJ/mol.
Q: What is second ionisation energy equation?
A: Second ionization energy is the energy required to remove an electron from an atom or molecule that has already lost one electron.
Q: What is the 2nd ionization energy?
A: The second ionization energy is the amount of energy needed to remove the second electron from an atom or molecule.
Q: How do you write the ionization energy of magnesium?
A: The ionization energy of magnesium is 7.65 eV.